131230222101113 has 2 divisors, whose sum is σ = 131230222101114. Its totient is φ = 131230222101112.

The previous prime is 131230222101101. The next prime is 131230222101131. The reversal of 131230222101113 is 311101222032131.

It is a happy number.

Together with next prime (131230222101131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97152800118544 + 34077421982569 = 9856612^2 + 5837587^2 .

It is a cyclic number.

It is not a de Polignac number, because 131230222101113 - 2¹⁴ = 131230222084729 is a prime.

It is not a weakly prime, because it can be changed into another prime (131230222101163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615111050556 + 65615111050557.

It is an arithmetic number, because the mean of its divisors is an integer number (65615111050557).

Almost surely, 2^{131230222101113} is an apocalyptic number.

It is an amenable number.

131230222101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131230222101113 is an equidigital number, since it uses as much as digits as its factorization.

131230222101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 131230222101113 its reverse (311101222032131), we get a palindrome (442331444133244).

The spelling of 131230222101113 in words is "one hundred thirty-one trillion, two hundred thirty billion, two hundred twenty-two million, one hundred one thousand, one hundred thirteen".