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1312304344342 = 2656152172171
BaseRepresentation
bin10011000110001011011…
…011110010110100010110
311122110021202010220112021
4103012023123302310112
5133000044403004332
62442510404243354
7163545060610405
oct23061333626426
94573252126467
101312304344342
114665aa655212
121924000a055a
139699931b274
144773178b63c
1524209261c97
hex1318b6f2d16

1312304344342 has 4 divisors (see below), whose sum is σ = 1968456516516. Its totient is φ = 656152172170.

The previous prime is 1312304344327. The next prime is 1312304344361. The reversal of 1312304344342 is 2434434032131.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1312304344298 and 1312304344307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328076086084 + ... + 328076086087.

It is an arithmetic number, because the mean of its divisors is an integer number (492114129129).

Almost surely, 21312304344342 is an apocalyptic number.

1312304344342 is a deficient number, since it is larger than the sum of its proper divisors (656152172174).

1312304344342 is an equidigital number, since it uses as much as digits as its factorization.

1312304344342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656152172173.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 1312304344342 its reverse (2434434032131), we get a palindrome (3746738376473).

The spelling of 1312304344342 in words is "one trillion, three hundred twelve billion, three hundred four million, three hundred forty-four thousand, three hundred forty-two".

Divisors: 1 2 656152172171 1312304344342