Base | Representation |
---|---|
bin | 10011000110001011011… |
… | …011110010110100010110 |
3 | 11122110021202010220112021 |
4 | 103012023123302310112 |
5 | 133000044403004332 |
6 | 2442510404243354 |
7 | 163545060610405 |
oct | 23061333626426 |
9 | 4573252126467 |
10 | 1312304344342 |
11 | 4665aa655212 |
12 | 1924000a055a |
13 | 9699931b274 |
14 | 4773178b63c |
15 | 24209261c97 |
hex | 1318b6f2d16 |
1312304344342 has 4 divisors (see below), whose sum is σ = 1968456516516. Its totient is φ = 656152172170.
The previous prime is 1312304344327. The next prime is 1312304344361. The reversal of 1312304344342 is 2434434032131.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1312304344298 and 1312304344307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328076086084 + ... + 328076086087.
It is an arithmetic number, because the mean of its divisors is an integer number (492114129129).
Almost surely, 21312304344342 is an apocalyptic number.
1312304344342 is a deficient number, since it is larger than the sum of its proper divisors (656152172174).
1312304344342 is an equidigital number, since it uses as much as digits as its factorization.
1312304344342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656152172173.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 1312304344342 its reverse (2434434032131), we get a palindrome (3746738376473).
The spelling of 1312304344342 in words is "one trillion, three hundred twelve billion, three hundred four million, three hundred forty-four thousand, three hundred forty-two".
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