Base | Representation |
---|---|
bin | 1011111011110111011001… |
… | …0111101001011110011111 |
3 | 1201110120001011120022102221 |
4 | 2332331312113221132133 |
5 | 3210002112403444332 |
6 | 43524401324330211 |
7 | 2523053632004503 |
oct | 276756627513637 |
9 | 51416034508387 |
10 | 13123110999967 |
11 | 41aa53104a171 |
12 | 157b41b3a3967 |
13 | 74267254c567 |
14 | 33523a5ca303 |
15 | 17b56780a297 |
hex | bef765e979f |
13123110999967 has 2 divisors, whose sum is σ = 13123110999968. Its totient is φ = 13123110999966.
The previous prime is 13123110999923. The next prime is 13123111000033. The reversal of 13123110999967 is 76999901132131.
It is a weak prime.
It is an emirp because it is prime and its reverse (76999901132131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123110999967 - 219 = 13123110475679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123110949967) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561555499983 + 6561555499984.
It is an arithmetic number, because the mean of its divisors is an integer number (6561555499984).
Almost surely, 213123110999967 is an apocalyptic number.
13123110999967 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123110999967 is an equidigital number, since it uses as much as digits as its factorization.
13123110999967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4960116, while the sum is 61.
The spelling of 13123110999967 in words is "thirteen trillion, one hundred twenty-three billion, one hundred ten million, nine hundred ninety-nine thousand, nine hundred sixty-seven".
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