Base | Representation |
---|---|
bin | 1011111011110111011001… |
… | …1111101100101010111001 |
3 | 1201110120001022112112010202 |
4 | 2332331312133230222321 |
5 | 3210002113424011301 |
6 | 43524401441451545 |
7 | 2523053655644003 |
oct | 276756637545271 |
9 | 51416038475122 |
10 | 13123113110201 |
11 | 41aa532260666 |
12 | 157b420040bb5 |
13 | 742672b0ac13 |
14 | 33523a9b9373 |
15 | 17b567ac566b |
hex | bef767ecab9 |
13123113110201 has 2 divisors, whose sum is σ = 13123113110202. Its totient is φ = 13123113110200.
The previous prime is 13123113110171. The next prime is 13123113110203. The reversal of 13123113110201 is 10201131132131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7712278855801 + 5410834254400 = 2777099^2 + 2326120^2 .
It is a cyclic number.
It is not a de Polignac number, because 13123113110201 - 226 = 13123046001337 is a prime.
Together with 13123113110203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13123113110203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561556555100 + 6561556555101.
It is an arithmetic number, because the mean of its divisors is an integer number (6561556555101).
Almost surely, 213123113110201 is an apocalyptic number.
It is an amenable number.
13123113110201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123113110201 is an equidigital number, since it uses as much as digits as its factorization.
13123113110201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 13123113110201 its reverse (10201131132131), we get a palindrome (23324244242332).
The spelling of 13123113110201 in words is "thirteen trillion, one hundred twenty-three billion, one hundred thirteen million, one hundred ten thousand, two hundred one".
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