13123113132301 has 4 divisors (see below), whose sum is σ = 13693683268512. Its totient is φ = 12552542996092.

The previous prime is 13123113132289. The next prime is 13123113132307. The reversal of 13123113132301 is 10323131132131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13123113132301 - 2³⁹ = 12573357318413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13123113132307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285285068071 + ... + 285285068116.

It is an arithmetic number, because the mean of its divisors is an integer number (3423420817128).

Almost surely, 2^{13123113132301} is an apocalyptic number.

It is an amenable number.

13123113132301 is a deficient number, since it is larger than the sum of its proper divisors (570570136211).

13123113132301 is an equidigital number, since it uses as much as digits as its factorization.

13123113132301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 570570136210.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13123113132301 its reverse (10323131132131), we get a palindrome (23446244264432).

The spelling of 13123113132301 in words is "thirteen trillion, one hundred twenty-three billion, one hundred thirteen million, one hundred thirty-two thousand, three hundred one".