Base | Representation |
---|---|
bin | 11000011100011001… |
… | …01111110000001001 |
3 | 1020212120110210011021 |
4 | 30032030233300021 |
5 | 203334004433413 |
6 | 10010110032441 |
7 | 643126500262 |
oct | 141614576011 |
9 | 36776423137 |
10 | 13123124233 |
11 | 562473051a |
12 | 2662aa8721 |
13 | 1311a5098b |
14 | 8c6c59969 |
15 | 51c17318d |
hex | 30e32fc09 |
13123124233 has 2 divisors, whose sum is σ = 13123124234. Its totient is φ = 13123124232.
The previous prime is 13123124213. The next prime is 13123124281. The reversal of 13123124233 is 33242132131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10386055744 + 2737068489 = 101912^2 + 52317^2 .
It is a cyclic number.
It is not a de Polignac number, because 13123124233 - 217 = 13122993161 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13123124198 and 13123124207.
It is not a weakly prime, because it can be changed into another prime (13123124213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561562116 + 6561562117.
It is an arithmetic number, because the mean of its divisors is an integer number (6561562117).
Almost surely, 213123124233 is an apocalyptic number.
It is an amenable number.
13123124233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123124233 is an equidigital number, since it uses as much as digits as its factorization.
13123124233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 25.
Adding to 13123124233 its reverse (33242132131), we get a palindrome (46365256364).
The spelling of 13123124233 in words is "thirteen billion, one hundred twenty-three million, one hundred twenty-four thousand, two hundred thirty-three".
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