Search a number
-
+
13123125524797 is a prime number
BaseRepresentation
bin1011111011110111011100…
…1111000011100100111101
31201110120002011220020202121
42332331313033003210331
53210002130113243142
643524403003522541
72523054166321111
oct276756717034475
951416064806677
1013123125524797
1141aa53926a962
12157b424229451
13742675566832
1433523c4cb741
1517b568c28c67
hexbef773c393d

13123125524797 has 2 divisors, whose sum is σ = 13123125524798. Its totient is φ = 13123125524796.

The previous prime is 13123125524791. The next prime is 13123125524837. The reversal of 13123125524797 is 79742552132131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7012015216441 + 6111110308356 = 2648021^2 + 2472066^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123125524797 - 219 = 13123125000509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13123125524791) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561562762398 + 6561562762399.

It is an arithmetic number, because the mean of its divisors is an integer number (6561562762399).

Almost surely, 213123125524797 is an apocalyptic number.

It is an amenable number.

13123125524797 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123125524797 is an equidigital number, since it uses as much as digits as its factorization.

13123125524797 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3175200, while the sum is 52.

The spelling of 13123125524797 in words is "thirteen trillion, one hundred twenty-three billion, one hundred twenty-five million, five hundred twenty-four thousand, seven hundred ninety-seven".