Base | Representation |
---|---|
bin | 1011111011110111110001… |
… | …1001000000110101111111 |
3 | 1201110120022012122201102002 |
4 | 2332331330121000311333 |
5 | 3210002314234133434 |
6 | 43524415333452515 |
7 | 2523056266452014 |
oct | 276757431006577 |
9 | 51416265581362 |
10 | 13123212021119 |
11 | 41aa583078922 |
12 | 157b4491a113b |
13 | 74268a45caa5 |
14 | 335249ba570b |
15 | 17b57161257e |
hex | bef7c640d7f |
13123212021119 has 2 divisors, whose sum is σ = 13123212021120. Its totient is φ = 13123212021118.
The previous prime is 13123212021097. The next prime is 13123212021173. The reversal of 13123212021119 is 91112021232131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13123212021119 - 236 = 13054492544383 is a prime.
It is a super-2 number, since 2×131232120211192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13123212021091 and 13123212021100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123212021319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561606010559 + 6561606010560.
It is an arithmetic number, because the mean of its divisors is an integer number (6561606010560).
Almost surely, 213123212021119 is an apocalyptic number.
13123212021119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123212021119 is an equidigital number, since it uses as much as digits as its factorization.
13123212021119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 29.
The spelling of 13123212021119 in words is "thirteen trillion, one hundred twenty-three billion, two hundred twelve million, twenty-one thousand, one hundred nineteen".
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