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131232140542351 is a prime number
BaseRepresentation
bin11101110101101011011101…
…000111101100000110001111
3122012122200002111211010012201
4131311223131013230012033
5114200101410434323401
61143035114005542331
736433131531414562
oct3565533507540617
9565580074733181
10131232140542351
11388a6269137512
12128758024149a7
13582c1a3849494
1424599531324d9
1510289b0c82b01
hex775add1ec18f

131232140542351 has 2 divisors, whose sum is σ = 131232140542352. Its totient is φ = 131232140542350.

The previous prime is 131232140542339. The next prime is 131232140542421. The reversal of 131232140542351 is 153245041232131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131232140542351 is a prime.

It is a super-2 number, since 2×1312321405423512 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131232140542351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131232140542651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616070271175 + 65616070271176.

It is an arithmetic number, because the mean of its divisors is an integer number (65616070271176).

Almost surely, 2131232140542351 is an apocalyptic number.

131232140542351 is a deficient number, since it is larger than the sum of its proper divisors (1).

131232140542351 is an equidigital number, since it uses as much as digits as its factorization.

131232140542351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 131232140542351 its reverse (153245041232131), we get a palindrome (284477181774482).

The spelling of 131232140542351 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, one hundred forty million, five hundred forty-two thousand, three hundred fifty-one".