Base | Representation |
---|---|
bin | 111101000111000011… |
… | …1010110100110001111 |
3 | 110112201212121221102102 |
4 | 1322032013112212033 |
5 | 4122231211423434 |
6 | 140142053145315 |
7 | 12324040511411 |
oct | 1721607264617 |
9 | 415655557372 |
10 | 131233311119 |
11 | 50723868019 |
12 | 2152592b23b |
13 | c4b5560121 |
14 | 64cd1ca9b1 |
15 | 363127e07e |
hex | 1e8e1d698f |
131233311119 has 2 divisors, whose sum is σ = 131233311120. Its totient is φ = 131233311118.
The previous prime is 131233311103. The next prime is 131233311149. The reversal of 131233311119 is 911113332131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131233311119 - 24 = 131233311103 is a prime.
It is a super-2 number, since 2×1312333111192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131233311091 and 131233311100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131233311149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616655559 + 65616655560.
It is an arithmetic number, because the mean of its divisors is an integer number (65616655560).
Almost surely, 2131233311119 is an apocalyptic number.
131233311119 is a deficient number, since it is larger than the sum of its proper divisors (1).
131233311119 is an equidigital number, since it uses as much as digits as its factorization.
131233311119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1458, while the sum is 29.
The spelling of 131233311119 in words is "one hundred thirty-one billion, two hundred thirty-three million, three hundred eleven thousand, one hundred nineteen".
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