131234023140133 has 2 divisors, whose sum is σ = 131234023140134. Its totient is φ = 131234023140132.

The previous prime is 131234023140091. The next prime is 131234023140161. The reversal of 131234023140133 is 331041320432131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130651826671809 + 582196468324 = 11430303^2 + 763018^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131234023140133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131234023140095 and 131234023140104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131234023120133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65617011570066 + 65617011570067.

It is an arithmetic number, because the mean of its divisors is an integer number (65617011570067).

Almost surely, 2^{131234023140133} is an apocalyptic number.

It is an amenable number.

131234023140133 is a deficient number, since it is larger than the sum of its proper divisors (1).

131234023140133 is an equidigital number, since it uses as much as digits as its factorization.

131234023140133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 131234023140133 its reverse (331041320432131), we get a palindrome (462275343572264).

The spelling of 131234023140133 in words is "one hundred thirty-one trillion, two hundred thirty-four billion, twenty-three million, one hundred forty thousand, one hundred thirty-three".