Base | Representation |
---|---|
bin | 1011111011111000100000… |
… | …1101000110010100111011 |
3 | 1201110120211000121111020221 |
4 | 2332332020031012110323 |
5 | 3210003221004140233 |
6 | 43524451134000511 |
7 | 2523064224244201 |
oct | 276761015062473 |
9 | 51416730544227 |
10 | 13123410224443 |
11 | 41aa674a43a22 |
12 | 157b4a3646137 |
13 | 7426bc53836c |
14 | 33526823b071 |
15 | 17b583c1442d |
hex | bef8834653b |
13123410224443 has 2 divisors, whose sum is σ = 13123410224444. Its totient is φ = 13123410224442.
The previous prime is 13123410224411. The next prime is 13123410224461. The reversal of 13123410224443 is 34442201432131.
It is a strong prime.
It is an emirp because it is prime and its reverse (34442201432131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123410224443 - 25 = 13123410224411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13123410224399 and 13123410224408.
It is not a weakly prime, because it can be changed into another prime (13123410221443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561705112221 + 6561705112222.
It is an arithmetic number, because the mean of its divisors is an integer number (6561705112222).
Almost surely, 213123410224443 is an apocalyptic number.
13123410224443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123410224443 is an equidigital number, since it uses as much as digits as its factorization.
13123410224443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 13123410224443 its reverse (34442201432131), we get a palindrome (47565611656574).
The spelling of 13123410224443 in words is "thirteen trillion, one hundred twenty-three billion, four hundred ten million, two hundred twenty-four thousand, four hundred forty-three".
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