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13123415131 is a prime number
BaseRepresentation
bin11000011100011011…
…10110110001011011
31020212121000120012021
430032031312301123
5203334043241011
610010120155311
7643132121341
oct141615666133
936777016167
1013123415131
11562490a032
122663008b37
131311b231c8
148c6cd3991
1551c1ce471
hex30e376c5b

13123415131 has 2 divisors, whose sum is σ = 13123415132. Its totient is φ = 13123415130.

The previous prime is 13123415119. The next prime is 13123415213. The reversal of 13123415131 is 13151432131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13123415131 - 25 = 13123415099 is a prime.

It is a super-2 number, since 2×131234151312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13123415096 and 13123415105.

It is not a weakly prime, because it can be changed into another prime (13133415131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561707565 + 6561707566.

It is an arithmetic number, because the mean of its divisors is an integer number (6561707566).

Almost surely, 213123415131 is an apocalyptic number.

13123415131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123415131 is an equidigital number, since it uses as much as digits as its factorization.

13123415131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1080, while the sum is 25.

Adding to 13123415131 its reverse (13151432131), we get a palindrome (26274847262).

The spelling of 13123415131 in words is "thirteen billion, one hundred twenty-three million, four hundred fifteen thousand, one hundred thirty-one".