Base | Representation |
---|---|
bin | 1011111011111001010010… |
… | …0000101111000000101010 |
3 | 1201110121100102010110021220 |
4 | 2332332110200233000222 |
5 | 3210004131333322120 |
6 | 43524523431242510 |
7 | 2523102312244131 |
oct | 276762440570052 |
9 | 51417312113256 |
10 | 13123616698410 |
11 | 41aa770548969 |
12 | 157b540819436 |
13 | 74272324b2ca |
14 | 335287826918 |
15 | 17b596debb40 |
hex | bef9482f02a |
13123616698410 has 16 divisors (see below), whose sum is σ = 31496680076256. Its totient is φ = 3499631119568.
The previous prime is 13123616698391. The next prime is 13123616698429. The reversal of 13123616698410 is 1489661632131.
13123616698410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13123616698391) and next prime (13123616698429).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218726944944 + ... + 218726945003.
It is an arithmetic number, because the mean of its divisors is an integer number (1968542504766).
Almost surely, 213123616698410 is an apocalyptic number.
13123616698410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13123616698410 is an abundant number, since it is smaller than the sum of its proper divisors (18373063377846).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13123616698410 is a wasteful number, since it uses less digits than its factorization.
13123616698410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437453889957.
The product of its (nonzero) digits is 1119744, while the sum is 51.
The spelling of 13123616698410 in words is "thirteen trillion, one hundred twenty-three billion, six hundred sixteen million, six hundred ninety-eight thousand, four hundred ten".
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