Base | Representation |
---|---|
bin | 111101000111010001… |
… | …0000110010100011011 |
3 | 110112202100211010222221 |
4 | 1322032202012110123 |
5 | 4122240010303311 |
6 | 140142503324511 |
7 | 12324154222306 |
oct | 1721642062433 |
9 | 415670733887 |
10 | 131240322331 |
11 | 50727816708 |
12 | 21528150737 |
13 | c4b6b46481 |
14 | 64d00d3b3d |
15 | 3631bb6671 |
hex | 1e8e88651b |
131240322331 has 2 divisors, whose sum is σ = 131240322332. Its totient is φ = 131240322330.
The previous prime is 131240322319. The next prime is 131240322407. The reversal of 131240322331 is 133223042131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131240322331 - 217 = 131240191259 is a prime.
It is a super-2 number, since 2×1312403223312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131240322296 and 131240322305.
It is not a weakly prime, because it can be changed into another prime (131240325331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620161165 + 65620161166.
It is an arithmetic number, because the mean of its divisors is an integer number (65620161166).
Almost surely, 2131240322331 is an apocalyptic number.
131240322331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131240322331 is an equidigital number, since it uses as much as digits as its factorization.
131240322331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131240322331 its reverse (133223042131), we get a palindrome (264463364462).
The spelling of 131240322331 in words is "one hundred thirty-one billion, two hundred forty million, three hundred twenty-two thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.117 sec. • engine limits •