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131240537 is a prime number
BaseRepresentation
bin1111101001010…
…01001001011001
3100010221201011122
413310221021121
5232044144122
621004535025
73152345321
oct764511131
9303851148
10131240537
1168099a5a
1237b51475
132126132c
1413604281
15b7c6142
hex7d29259

131240537 has 2 divisors, whose sum is σ = 131240538. Its totient is φ = 131240536.

The previous prime is 131240533. The next prime is 131240563. The reversal of 131240537 is 735042131.

It is an a-pointer prime, because the next prime (131240563) can be obtained adding 131240537 to its sum of digits (26).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111429136 + 19811401 = 10556^2 + 4451^2 .

It is a cyclic number.

It is not a de Polignac number, because 131240537 - 22 = 131240533 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131240533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620268 + 65620269.

It is an arithmetic number, because the mean of its divisors is an integer number (65620269).

Almost surely, 2131240537 is an apocalyptic number.

It is an amenable number.

131240537 is a deficient number, since it is larger than the sum of its proper divisors (1).

131240537 is an equidigital number, since it uses as much as digits as its factorization.

131240537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 26.

The square root of 131240537 is about 11456.0262307661. The cubic root of 131240537 is about 508.1859645790.

Adding to 131240537 its reverse (735042131), we get a palindrome (866282668).

The spelling of 131240537 in words is "one hundred thirty-one million, two hundred forty thousand, five hundred thirty-seven".