Search a number
-
+
1312413020389 is a prime number
BaseRepresentation
bin10011000110010001111…
…010010111000011100101
311122110120022122020001001
4103012101322113003211
5133000310213123024
62442525245433301
7163550550416242
oct23062172270345
94573508566031
101312413020389
11466655a32129
1219243056b831
13969b59abb13
1447741d9a5c9
1524213a7c244
hex13191e970e5

1312413020389 has 2 divisors, whose sum is σ = 1312413020390. Its totient is φ = 1312413020388.

The previous prime is 1312413020377. The next prime is 1312413020431. The reversal of 1312413020389 is 9830203142131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 749375892225 + 563037128164 = 865665^2 + 750358^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312413020389 - 215 = 1312412987621 is a prime.

It is a super-2 number, since 2×13124130203892 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312413020309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656206510194 + 656206510195.

It is an arithmetic number, because the mean of its divisors is an integer number (656206510195).

Almost surely, 21312413020389 is an apocalyptic number.

It is an amenable number.

1312413020389 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312413020389 is an equidigital number, since it uses as much as digits as its factorization.

1312413020389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 1312413020389 in words is "one trillion, three hundred twelve billion, four hundred thirteen million, twenty thousand, three hundred eighty-nine".