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131241363142157 is a prime number
BaseRepresentation
bin11101110101110100000010…
…110101000111011000001101
3122012200112220020202201202022
4131311310002311013120031
5114200224302431022112
61143043241102135525
736433606216260632
oct3565640265073015
9565615806681668
10131241363142157
11388aa171047224
1212877556b815a5
135830013467628
14245a189d30189
151028d5077ed72
hex775d02d4760d

131241363142157 has 2 divisors, whose sum is σ = 131241363142158. Its totient is φ = 131241363142156.

The previous prime is 131241363142069. The next prime is 131241363142187. The reversal of 131241363142157 is 751241363142131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79794397738441 + 51446965403716 = 8932771^2 + 7172654^2 .

It is a cyclic number.

It is not a de Polignac number, because 131241363142157 - 28 = 131241363141901 is a prime.

It is a super-2 number, since 2×1312413631421572 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131241363142187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620681571078 + 65620681571079.

It is an arithmetic number, because the mean of its divisors is an integer number (65620681571079).

Almost surely, 2131241363142157 is an apocalyptic number.

It is an amenable number.

131241363142157 is a deficient number, since it is larger than the sum of its proper divisors (1).

131241363142157 is an equidigital number, since it uses as much as digits as its factorization.

131241363142157 is an evil number, because the sum of its binary digits is even.

The product of its digits is 362880, while the sum is 44.

The spelling of 131241363142157 in words is "one hundred thirty-one trillion, two hundred forty-one billion, three hundred sixty-three million, one hundred forty-two thousand, one hundred fifty-seven".