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131241401214000 = 243537111012812597
BaseRepresentation
bin11101110101110100000101…
…000110010110010000110000
3122012200112222220101222111120
4131311310011012112100300
5114200224342202322000
61143043244542142240
736433610161005360
oct3565640506262060
9565615886358446
10131241401214000
11388aa190590160
1212877567881980
13583001b30764c
14245a1910009a0
151028d53ca06a0
hex775d05196430

131241401214000 has 640 divisors, whose sum is σ = 532752322811904. Its totient is φ = 27000921600000.

The previous prime is 131241401213963. The next prime is 131241401214037. The reversal of 131241401214000 is 412104142131.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (131241401213963) and next prime (131241401214037).

It is a super-2 number, since 2×1312414012140002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 45255702 + ... + 48068298.

Almost surely, 2131241401214000 is an apocalyptic number.

131241401214000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131241401214000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (266376161405952).

131241401214000 is an abundant number, since it is smaller than the sum of its proper divisors (401510921597904).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131241401214000 is a wasteful number, since it uses less digits than its factorization.

131241401214000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2812742 (or 2812726 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 131241401214000 its reverse (412104142131), we get a palindrome (131653505356131).

The spelling of 131241401214000 in words is "one hundred thirty-one trillion, two hundred forty-one billion, four hundred one million, two hundred fourteen thousand".