13124141233033 has 2 divisors, whose sum is σ = 13124141233034. Its totient is φ = 13124141233032.

The previous prime is 13124141233031. The next prime is 13124141233043. The reversal of 13124141233033 is 33033214142131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12579846988864 + 544294244169 = 3546808^2 + 737763^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124141233033 - 2¹ = 13124141233031 is a prime.

It is a super-3 number, since 3×13124141233033³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13124141233031, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13124141232986 and 13124141233004.

It is not a weakly prime, because it can be changed into another prime (13124141233031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562070616516 + 6562070616517.

It is an arithmetic number, because the mean of its divisors is an integer number (6562070616517).

Almost surely, 2^{13124141233033} is an apocalyptic number.

It is an amenable number.

13124141233033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124141233033 is an equidigital number, since it uses as much as digits as its factorization.

13124141233033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13124141233033 its reverse (33033214142131), we get a palindrome (46157355375164).

The spelling of 13124141233033 in words is "thirteen trillion, one hundred twenty-four billion, one hundred forty-one million, two hundred thirty-three thousand, thirty-three".