Search a number
-
+
1312414204433 is a prime number
BaseRepresentation
bin10011000110010001111…
…110111000001000010001
311122110120101212101020112
4103012101332320020101
5133000311014020213
62442525331051105
7163550563450253
oct23062176701021
94573511771215
101312414204433
11466656670782
12192430a40a95
13969b6004a37
14477421c7cd3
1524213c12ea8
hex13191fb8211

1312414204433 has 2 divisors, whose sum is σ = 1312414204434. Its totient is φ = 1312414204432.

The previous prime is 1312414204421. The next prime is 1312414204459. The reversal of 1312414204433 is 3344024142131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1016894761744 + 295519442689 = 1008412^2 + 543617^2 .

It is an emirp because it is prime and its reverse (3344024142131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312414204433 - 224 = 1312397427217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1312414204433.

It is not a weakly prime, because it can be changed into another prime (1312414204733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656207102216 + 656207102217.

It is an arithmetic number, because the mean of its divisors is an integer number (656207102217).

Almost surely, 21312414204433 is an apocalyptic number.

It is an amenable number.

1312414204433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312414204433 is an equidigital number, since it uses as much as digits as its factorization.

1312414204433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1312414204433 its reverse (3344024142131), we get a palindrome (4656438346564).

The spelling of 1312414204433 in words is "one trillion, three hundred twelve billion, four hundred fourteen million, two hundred four thousand, four hundred thirty-three".