Search a number
-
+
1312414240301 is a prime number
BaseRepresentation
bin10011000110010001111…
…111000000111000101101
311122110120101221012102222
4103012101333000320231
5133000311021142201
62442525331525125
7163550563656653
oct23062177007055
94573511835388
101312414240301
1146665669571a
12192430a597a5
13969b6018168
14477421d6dd3
1524213c1d91b
hex13191fc0e2d

1312414240301 has 2 divisors, whose sum is σ = 1312414240302. Its totient is φ = 1312414240300.

The previous prime is 1312414240273. The next prime is 1312414240349. The reversal of 1312414240301 is 1030424142131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1260578790025 + 51835450276 = 1122755^2 + 227674^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312414240301 is a prime.

It is a super-2 number, since 2×13124142403012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312414240801) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656207120150 + 656207120151.

It is an arithmetic number, because the mean of its divisors is an integer number (656207120151).

Almost surely, 21312414240301 is an apocalyptic number.

It is an amenable number.

1312414240301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312414240301 is an equidigital number, since it uses as much as digits as its factorization.

1312414240301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 1312414240301 its reverse (1030424142131), we get a palindrome (2342838382432).

The spelling of 1312414240301 in words is "one trillion, three hundred twelve billion, four hundred fourteen million, two hundred forty thousand, three hundred one".