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13124204431342 = 257111492298101
BaseRepresentation
bin1011111011111011011110…
…0010110000011111101110
31201110122212101001101022021
42332332313202300133232
53210011332313300332
643525102024340354
72523123010012204
oct276766742603756
951418771041267
1013124204431342
1141aaa42288364
12157b6856146ba
137427b7c40484
143353018d9074
1517b5cd7e4c97
hexbefb78b07ee

13124204431342 has 8 divisors (see below), whose sum is σ = 19720783543032. Its totient is φ = 6550609917000.

The previous prime is 13124204431321. The next prime is 13124204431357. The reversal of 13124204431342 is 24313440242131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13124204431298 and 13124204431307.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5746147909 + ... + 5746150192.

It is an arithmetic number, because the mean of its divisors is an integer number (2465097942879).

Almost surely, 213124204431342 is an apocalyptic number.

13124204431342 is a deficient number, since it is larger than the sum of its proper divisors (6596579111690).

13124204431342 is a wasteful number, since it uses less digits than its factorization.

13124204431342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11492298674.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 13124204431342 its reverse (24313440242131), we get a palindrome (37437644673473).

The spelling of 13124204431342 in words is "thirteen trillion, one hundred twenty-four billion, two hundred four million, four hundred thirty-one thousand, three hundred forty-two".

Divisors: 1 2 571 1142 11492298101 22984596202 6562102215671 13124204431342