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13124231043397 is a prime number
BaseRepresentation
bin1011111011111011100100…
…1000010001100101000101
31201110122221020010102011221
42332332321020101211011
53210011411121342042
643525104415000341
72523123452140315
oct276767110214505
951418836112157
1013124231043397
1141aaa563043a1
12157b6925090b1
137427c05ca356
14335305265445
1517b5d0ceed67
hexbefb9211945

13124231043397 has 2 divisors, whose sum is σ = 13124231043398. Its totient is φ = 13124231043396.

The previous prime is 13124231043359. The next prime is 13124231043409. The reversal of 13124231043397 is 79334013242131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12936747239361 + 187483804036 = 3596769^2 + 432994^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124231043397 - 219 = 13124230519109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124231443397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562115521698 + 6562115521699.

It is an arithmetic number, because the mean of its divisors is an integer number (6562115521699).

Almost surely, 213124231043397 is an apocalyptic number.

It is an amenable number.

13124231043397 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124231043397 is an equidigital number, since it uses as much as digits as its factorization.

13124231043397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 43.

The spelling of 13124231043397 in words is "thirteen trillion, one hundred twenty-four billion, two hundred thirty-one million, forty-three thousand, three hundred ninety-seven".