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13124233441440 = 25325112336023917
BaseRepresentation
bin1011111011111011100101…
…0001011011000010100000
31201110122221101122020200100
42332332321101123002200
53210011412230111230
643525104542222400
72523123511415562
oct276767121330240
951418841566610
1013124233441440
1141aaa576a2050
12157b693284a00
137427c0c59a04
143353056cb332
1517b5d1125660
hexbefb945b0a0

13124233441440 has 288 divisors, whose sum is σ = 50982201518976. Its totient is φ = 3043300423680.

The previous prime is 13124233441393. The next prime is 13124233441441. The reversal of 13124233441440 is 4414433242131.

13124233441440 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 4 + 233 + 4 + 414 + 4 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (288).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 13124233441395 and 13124233441404.

It is not an unprimeable number, because it can be changed into a prime (13124233441441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 17647639 + ... + 18376278.

It is an arithmetic number, because the mean of its divisors is an integer number (177021533052).

Almost surely, 213124233441440 is an apocalyptic number.

13124233441440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13124233441440 is an abundant number, since it is smaller than the sum of its proper divisors (37857968077536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13124233441440 is a wasteful number, since it uses less digits than its factorization.

13124233441440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36023972 (or 36023961 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 36.

Adding to 13124233441440 its reverse (4414433242131), we get a palindrome (17538666683571).

The spelling of 13124233441440 in words is "thirteen trillion, one hundred twenty-four billion, two hundred thirty-three million, four hundred forty-one thousand, four hundred forty".