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1312431426037 is a prime number
BaseRepresentation
bin10011000110010011000…
…000100100100111110101
311122110121121021022211201
4103012103000210213311
5133000324421113122
62442531144132501
7163551163025104
oct23062300444765
94573547238751
101312431426037
11466665363606
12192436767131
13969b9754634
14477445cc03b
15242154b5a27
hex131930249f5

1312431426037 has 2 divisors, whose sum is σ = 1312431426038. Its totient is φ = 1312431426036.

The previous prime is 1312431426011. The next prime is 1312431426043. The reversal of 1312431426037 is 7306241342131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1097882744401 + 214548681636 = 1047799^2 + 463194^2 .

It is an emirp because it is prime and its reverse (7306241342131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312431426037 - 227 = 1312297208309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312431425987 and 1312431426005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312431426077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656215713018 + 656215713019.

It is an arithmetic number, because the mean of its divisors is an integer number (656215713019).

Almost surely, 21312431426037 is an apocalyptic number.

It is an amenable number.

1312431426037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312431426037 is an equidigital number, since it uses as much as digits as its factorization.

1312431426037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576, while the sum is 37.

Adding to 1312431426037 its reverse (7306241342131), we get a palindrome (8618672768168).

The spelling of 1312431426037 in words is "one trillion, three hundred twelve billion, four hundred thirty-one million, four hundred twenty-six thousand, thirty-seven".