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13124333133437 is a prime number
BaseRepresentation
bin1011111011111011111100…
…1101101101111001111101
31201110200012100020010101112
42332332333031231321331
53210012113240232222
643525122503051405
72523126131656031
oct276767715557175
951420170203345
1013124333133437
1141aaaa89a3129
12157b700740b65
137428087c3266
14335314a3c1c1
1517b5d9c68be2
hexbefbf36de7d

13124333133437 has 2 divisors, whose sum is σ = 13124333133438. Its totient is φ = 13124333133436.

The previous prime is 13124333133383. The next prime is 13124333133467. The reversal of 13124333133437 is 73433133342131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11003424413881 + 2120908719556 = 3317141^2 + 1456334^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124333133437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124333133394 and 13124333133403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124333133467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562166566718 + 6562166566719.

It is an arithmetic number, because the mean of its divisors is an integer number (6562166566719).

Almost surely, 213124333133437 is an apocalyptic number.

It is an amenable number.

13124333133437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124333133437 is an equidigital number, since it uses as much as digits as its factorization.

13124333133437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 489888, while the sum is 41.

Adding to 13124333133437 its reverse (73433133342131), we get a palindrome (86557466475568).

The spelling of 13124333133437 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-three million, one hundred thirty-three thousand, four hundred thirty-seven".