Base | Representation |
---|---|
bin | 10011000110010011001… |
… | …010111001000010011111 |
3 | 11122110121210100202111100 |
4 | 103012103022321002133 |
5 | 133000331114143403 |
6 | 2442531322124143 |
7 | 163551225022434 |
oct | 23062312710237 |
9 | 4573553322440 |
10 | 1312434131103 |
11 | 4666669409a7 |
12 | 192437650653 |
13 | 969ba190974 |
14 | 47744ad3b8b |
15 | 2421584c2a3 |
hex | 131932b909f |
1312434131103 has 24 divisors (see below), whose sum is σ = 1936902240000. Its totient is φ = 855973241424.
The previous prime is 1312434131069. The next prime is 1312434131117. The reversal of 1312434131103 is 3011314342131.
1312434131103 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 4 + 341 + 311 + 0 + 3 = 666.
It is not a de Polignac number, because 1312434131103 - 210 = 1312434130079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312434131803) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 326148 + ... + 1652646.
It is an arithmetic number, because the mean of its divisors is an integer number (80704260000).
Almost surely, 21312434131103 is an apocalyptic number.
1312434131103 is a deficient number, since it is larger than the sum of its proper divisors (624468108897).
1312434131103 is a wasteful number, since it uses less digits than its factorization.
1312434131103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1328891 (or 1328888 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 1312434131103 its reverse (3011314342131), we get a palindrome (4323748473234).
The spelling of 1312434131103 in words is "one trillion, three hundred twelve billion, four hundred thirty-four million, one hundred thirty-one thousand, one hundred three".
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