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131244111001 is a prime number
BaseRepresentation
bin111101000111011000…
…0100011010010011001
3110112202121221122002001
41322032300203102121
54122241443023001
6140143120441001
712324231352063
oct1721660432231
9415677848061
10131244111001
1150729974143
1221529479161
13c4b7871aa3
1464d07dc733
1536321b4001
hex1e8ec23499

131244111001 has 2 divisors, whose sum is σ = 131244111002. Its totient is φ = 131244111000.

The previous prime is 131244110981. The next prime is 131244111041. The reversal of 131244111001 is 100111442131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79989414976 + 51254696025 = 282824^2 + 226395^2 .

It is a cyclic number.

It is not a de Polignac number, because 131244111001 - 27 = 131244110873 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131244111001.

It is not a weakly prime, because it can be changed into another prime (131244111041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65622055500 + 65622055501.

It is an arithmetic number, because the mean of its divisors is an integer number (65622055501).

Almost surely, 2131244111001 is an apocalyptic number.

It is an amenable number.

131244111001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131244111001 is an equidigital number, since it uses as much as digits as its factorization.

131244111001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 131244111001 its reverse (100111442131), we get a palindrome (231355553132).

The spelling of 131244111001 in words is "one hundred thirty-one billion, two hundred forty-four million, one hundred eleven thousand, one".