Base | Representation |
---|---|
bin | 1011111011111100010011… |
… | …1111011001000011111011 |
3 | 1201110200110002120120001002 |
4 | 2332333010333121003323 |
5 | 3210012313042310324 |
6 | 43525140244115215 |
7 | 2523131416452251 |
oct | 276770477310373 |
9 | 51420402516032 |
10 | 13124430041339 |
11 | 4200048672501 |
12 | 157b729095b0b |
13 | 7428228c3506 |
14 | 3353238665d1 |
15 | 17b5e350c3ae |
hex | befc4fd90fb |
13124430041339 has 2 divisors, whose sum is σ = 13124430041340. Its totient is φ = 13124430041338.
The previous prime is 13124430041311. The next prime is 13124430041357. The reversal of 13124430041339 is 93314003442131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13124430041339 is a prime.
It is not a weakly prime, because it can be changed into another prime (13124430041309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562215020669 + 6562215020670.
It is an arithmetic number, because the mean of its divisors is an integer number (6562215020670).
Almost surely, 213124430041339 is an apocalyptic number.
13124430041339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124430041339 is an equidigital number, since it uses as much as digits as its factorization.
13124430041339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 38.
The spelling of 13124430041339 in words is "thirteen trillion, one hundred twenty-four billion, four hundred thirty million, forty-one thousand, three hundred thirty-nine".
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