Base | Representation |
---|---|
bin | 1011111011111100010111… |
… | …0001101101101011011011 |
3 | 1201110200111000101202120122 |
4 | 2332333011301231223123 |
5 | 3210012324431423422 |
6 | 43525141434543455 |
7 | 2523131636544002 |
oct | 276770561555333 |
9 | 51420430352518 |
10 | 13124443232987 |
11 | 4200055062599 |
12 | 157b731597b8b |
13 | 742825561a18 |
14 | 3353254dbc39 |
15 | 17b5e4765d42 |
hex | befc5c6dadb |
13124443232987 has 2 divisors, whose sum is σ = 13124443232988. Its totient is φ = 13124443232986.
The previous prime is 13124443232969. The next prime is 13124443233037. The reversal of 13124443232987 is 78923234442131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13124443232987 - 224 = 13124426455771 is a prime.
It is not a weakly prime, because it can be changed into another prime (13124443232387) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562221616493 + 6562221616494.
It is an arithmetic number, because the mean of its divisors is an integer number (6562221616494).
Almost surely, 213124443232987 is an apocalyptic number.
13124443232987 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124443232987 is an equidigital number, since it uses as much as digits as its factorization.
13124443232987 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6967296, while the sum is 53.
The spelling of 13124443232987 in words is "thirteen trillion, one hundred twenty-four billion, four hundred forty-three million, two hundred thirty-two thousand, nine hundred eighty-seven".
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