1312494013 has 2 divisors, whose sum is σ = 1312494014. Its totient is φ = 1312494012.

The previous prime is 1312493981. The next prime is 1312494019. The reversal of 1312494013 is 3104942131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1187009209 + 125484804 = 34453^2 + 11202^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312494013 - 2⁵ = 1312493981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312494019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656247006 + 656247007.

It is an arithmetic number, because the mean of its divisors is an integer number (656247007).

Almost surely, 2^1312494013 is an apocalyptic number.

It is an amenable number.

1312494013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312494013 is an equidigital number, since it uses as much as digits as its factorization.

1312494013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 28.

The square root of 1312494013 is about 36228.3592369293. The cubic root of 1312494013 is about 1094.8781201960.

The spelling of 1312494013 in words is "one billion, three hundred twelve million, four hundred ninety-four thousand, thirteen".