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1312531263247 is a prime number
BaseRepresentation
bin10011000110011000111…
…101011010111100001111
311122110212120010120202011
4103012120331122330033
5133001031000410442
62442545112042051
7163553514441511
oct23063075327417
94573776116664
101312531263247
114667067537a6
12192464093327
1396a0433bcc9
1447753979bb1
152421e137117
hex13198f5af0f

1312531263247 has 2 divisors, whose sum is σ = 1312531263248. Its totient is φ = 1312531263246.

The previous prime is 1312531263229. The next prime is 1312531263259. The reversal of 1312531263247 is 7423621352131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312531263247 is a prime.

It is a super-2 number, since 2×13125312632472 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312531263947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656265631623 + 656265631624.

It is an arithmetic number, because the mean of its divisors is an integer number (656265631624).

Almost surely, 21312531263247 is an apocalyptic number.

1312531263247 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312531263247 is an equidigital number, since it uses as much as digits as its factorization.

1312531263247 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 181440, while the sum is 40.

The spelling of 1312531263247 in words is "one trillion, three hundred twelve billion, five hundred thirty-one million, two hundred sixty-three thousand, two hundred forty-seven".