Base | Representation |
---|---|
bin | 1011111011111111101010… |
… | …1101100101001011100111 |
3 | 1201110202202220112101012002 |
4 | 2332333322231211023213 |
5 | 3210021134310421210 |
6 | 43525405522115515 |
7 | 2523162642416162 |
oct | 276777255451347 |
9 | 51422686471162 |
10 | 13125331342055 |
11 | 4200470403029 |
12 | 157b93aaabb9b |
13 | 742937553c4a |
14 | 3353ab440ad9 |
15 | 17b6476e44a5 |
hex | beffab652e7 |
13125331342055 has 8 divisors (see below), whose sum is σ = 15769396888800. Its totient is φ = 10487598888096.
The previous prime is 13125331342051. The next prime is 13125331342087. The reversal of 13125331342055 is 55024313352131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13125331342055 - 22 = 13125331342051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13125331342051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1583268635 + ... + 1583276924.
It is an arithmetic number, because the mean of its divisors is an integer number (1971174611100).
Almost surely, 213125331342055 is an apocalyptic number.
13125331342055 is a deficient number, since it is larger than the sum of its proper divisors (2644065546745).
13125331342055 is an equidigital number, since it uses as much as digits as its factorization.
13125331342055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3166546393.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 13125331342055 its reverse (55024313352131), we get a palindrome (68149644694186).
The spelling of 13125331342055 in words is "thirteen trillion, one hundred twenty-five billion, three hundred thirty-one million, three hundred forty-two thousand, fifty-five".
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