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1312540211 is a prime number
BaseRepresentation
bin100111000111011…
…1100011000110011
310101110202221200102
41032032330120303
510142002241321
6334124143015
744345256563
oct11616743063
93343687612
101312540211
11613992984
12307697a6b
1317bc08b18
14c6466da3
157a36ac0b
hex4e3bc633

1312540211 has 2 divisors, whose sum is σ = 1312540212. Its totient is φ = 1312540210.

The previous prime is 1312540193. The next prime is 1312540231. The reversal of 1312540211 is 1120452131.

It is an a-pointer prime, because the next prime (1312540231) can be obtained adding 1312540211 to its sum of digits (20).

It is a weak prime.

It is an emirp because it is prime and its reverse (1120452131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312540211 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312540231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656270105 + 656270106.

It is an arithmetic number, because the mean of its divisors is an integer number (656270106).

Almost surely, 21312540211 is an apocalyptic number.

1312540211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312540211 is an equidigital number, since it uses as much as digits as its factorization.

1312540211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 1312540211 is about 36228.9968257472. The cubic root of 1312540211 is about 1094.8909661177.

Adding to 1312540211 its reverse (1120452131), we get a palindrome (2432992342).

The spelling of 1312540211 in words is "one billion, three hundred twelve million, five hundred forty thousand, two hundred eleven".