Base | Representation |
---|---|
bin | 1011111011111111111100… |
… | …0111011100011110100111 |
3 | 1201110202222001120022210020 |
4 | 2332333333013130132213 |
5 | 3210021312214343030 |
6 | 43525421121530223 |
7 | 2523164530440660 |
oct | 276777707343647 |
9 | 51422861508706 |
10 | 13125405231015 |
11 | 42004a908a990 |
12 | 157b95b7a3973 |
13 | 74294995491c |
14 | 3353b7196367 |
15 | 17b64de3c510 |
hex | befff1dc7a7 |
13125405231015 has 32 divisors (see below), whose sum is σ = 26182626541056. Its totient is φ = 5454713861760.
The previous prime is 13125405231007. The next prime is 13125405231091. The reversal of 13125405231015 is 51013250452131.
It is not a de Polignac number, because 13125405231015 - 23 = 13125405231007 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5681992452 + ... + 5681994761.
It is an arithmetic number, because the mean of its divisors is an integer number (818207079408).
Almost surely, 213125405231015 is an apocalyptic number.
13125405231015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13125405231015 is a deficient number, since it is larger than the sum of its proper divisors (13057221310041).
13125405231015 is a wasteful number, since it uses less digits than its factorization.
13125405231015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11363987239.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 13125405231015 its reverse (51013250452131), we get a palindrome (64138655683146).
The spelling of 13125405231015 in words is "thirteen trillion, one hundred twenty-five billion, four hundred five million, two hundred thirty-one thousand, fifteen".
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