Base | Representation |
---|---|
bin | 1011111011111111111100… |
… | …0111011100011110100110 |
3 | 1201110202222001120022210012 |
4 | 2332333333013130132212 |
5 | 3210021312214343024 |
6 | 43525421121530222 |
7 | 2523164530440656 |
oct | 276777707343646 |
9 | 51422861508705 |
10 | 13125405231014 |
11 | 42004a908a98a |
12 | 157b95b7a3972 |
13 | 74294995491b |
14 | 3353b7196366 |
15 | 17b64de3c50e |
hex | befff1dc7a6 |
13125405231014 has 4 divisors (see below), whose sum is σ = 19688107846524. Its totient is φ = 6562702615506.
The previous prime is 13125405231007. The next prime is 13125405231091. The reversal of 13125405231014 is 41013250452131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281351307752 + ... + 3281351307755.
It is an arithmetic number, because the mean of its divisors is an integer number (4922026961631).
Almost surely, 213125405231014 is an apocalyptic number.
13125405231014 is a deficient number, since it is larger than the sum of its proper divisors (6562702615510).
13125405231014 is an equidigital number, since it uses as much as digits as its factorization.
13125405231014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6562702615509.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13125405231014 its reverse (41013250452131), we get a palindrome (54138655683145).
The spelling of 13125405231014 in words is "thirteen trillion, one hundred twenty-five billion, four hundred five million, two hundred thirty-one thousand, fourteen".
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