13125440431031 has 4 divisors (see below), whose sum is σ = 13125449173200. Its totient is φ = 13125431688864.

The previous prime is 13125440430983. The next prime is 13125440431043. The reversal of 13125440431031 is 13013404452131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13125440431031 - 2¹⁰ = 13125440430007 is a prime.

It is a super-2 number, since 2×13125440431031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125440431091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1482851 + ... + 5333828.

It is an arithmetic number, because the mean of its divisors is an integer number (3281362293300).

Almost surely, 2^{13125440431031} is an apocalyptic number.

13125440431031 is a deficient number, since it is larger than the sum of its proper divisors (8742169).

13125440431031 is an equidigital number, since it uses as much as digits as its factorization.

13125440431031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8742168.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 13125440431031 its reverse (13013404452131), we get a palindrome (26138844883162).

The spelling of 13125440431031 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty million, four hundred thirty-one thousand, thirty-one".