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13125440431042 = 27915438291047
BaseRepresentation
bin1011111100000000000100…
…1101101110001111000010
31201110210001111210200010221
42333000001031232033002
53210021400222243132
643525424420213254
72523165435564652
oct277000115561702
951423044720127
1013125440431042
114200516a42215
12157b96b53a22a
1374295402a744
143353bbb1a362
1517b652091e97
hexbf00136e3c2

13125440431042 has 8 divisors (see below), whose sum is σ = 19688187894336. Its totient is φ = 6562711132932.

The previous prime is 13125440430983. The next prime is 13125440431043. The reversal of 13125440431042 is 24013404452131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13125440430989 and 13125440431007.

It is not an unprimeable number, because it can be changed into a prime (13125440431043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2562438 + ... + 5728609.

It is an arithmetic number, because the mean of its divisors is an integer number (2461023486792).

Almost surely, 213125440431042 is an apocalyptic number.

13125440431042 is a deficient number, since it is larger than the sum of its proper divisors (6562747463294).

13125440431042 is an equidigital number, since it uses as much as digits as its factorization.

13125440431042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9082592.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 13125440431042 its reverse (24013404452131), we get a palindrome (37138844883173).

The spelling of 13125440431042 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty million, four hundred thirty-one thousand, forty-two".

Divisors: 1 2 791543 1583086 8291047 16582094 6562720215521 13125440431042