13125440439043 has 2 divisors, whose sum is σ = 13125440439044. Its totient is φ = 13125440439042.

The previous prime is 13125440439037. The next prime is 13125440439157. The reversal of 13125440439043 is 34093404452131.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (34093404452131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13125440439043 - 2⁴¹ = 10926417183491 is a prime.

It is not a weakly prime, because it can be changed into another prime (13125440439743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562720219521 + 6562720219522.

It is an arithmetic number, because the mean of its divisors is an integer number (6562720219522).

Almost surely, 2^{13125440439043} is an apocalyptic number.

13125440439043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125440439043 is an equidigital number, since it uses as much as digits as its factorization.

13125440439043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 622080, while the sum is 43.

The spelling of 13125440439043 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty million, four hundred thirty-nine thousand, forty-three".