Base | Representation |
---|---|
bin | 1011111100000000000101… |
… | …1101010000000000011110 |
3 | 1201110210001210110110210220 |
4 | 2333000001131100000132 |
5 | 3210021402243022114 |
6 | 43525425043342210 |
7 | 2523165515310201 |
oct | 277000135200036 |
9 | 51423053413726 |
10 | 13125444501534 |
11 | 4200519272462 |
12 | 157b970981966 |
13 | 742954b24411 |
14 | 3353bc499938 |
15 | 17b6525e80a9 |
hex | bf00175001e |
13125444501534 has 32 divisors (see below), whose sum is σ = 26360656743456. Its totient is φ = 4356881802240.
The previous prime is 13125444501527. The next prime is 13125444501539. The reversal of 13125444501534 is 43510544452131.
It is a super-2 number, since 2×131254445015342 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13125444501539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1673407 + ... + 5389914.
It is an arithmetic number, because the mean of its divisors is an integer number (823770523233).
Almost surely, 213125444501534 is an apocalyptic number.
13125444501534 is an abundant number, since it is smaller than the sum of its proper divisors (13235212241922).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13125444501534 is a wasteful number, since it uses less digits than its factorization.
13125444501534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7064620.
The product of its (nonzero) digits is 576000, while the sum is 42.
Adding to 13125444501534 its reverse (43510544452131), we get a palindrome (56635988953665).
The spelling of 13125444501534 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-four million, five hundred one thousand, five hundred thirty-four".
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