13125444520351 has 2 divisors, whose sum is σ = 13125444520352. Its totient is φ = 13125444520350.

The previous prime is 13125444520337. The next prime is 13125444520369. The reversal of 13125444520351 is 15302544452131.

13125444520351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13125444520351 - 2⁵ = 13125444520319 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13125444520151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562722260175 + 6562722260176.

It is an arithmetic number, because the mean of its divisors is an integer number (6562722260176).

Almost surely, 2^{13125444520351} is an apocalyptic number.

13125444520351 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125444520351 is an equidigital number, since it uses as much as digits as its factorization.

13125444520351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 13125444520351 its reverse (15302544452131), we get a palindrome (28427988972482).

The spelling of 13125444520351 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-four million, five hundred twenty thousand, three hundred fifty-one".