Base | Representation |
---|---|
bin | 1011111100000000000101… |
… | …1111010001000011100000 |
3 | 1201110210001211110022212212 |
4 | 2333000001133101003200 |
5 | 3210021402411430422 |
6 | 43525425102541252 |
7 | 2523165522641222 |
oct | 277000137210340 |
9 | 51423054408785 |
10 | 13125445030112 |
11 | 42005195a35a8 |
12 | 157b970b97828 |
13 | 742954c7ab9c |
14 | 3353bc596412 |
15 | 17b65269e9e2 |
hex | bf0017d10e0 |
13125445030112 has 12 divisors (see below), whose sum is σ = 25840719903096. Its totient is φ = 6562722515040.
The previous prime is 13125445030063. The next prime is 13125445030129. The reversal of 13125445030112 is 21103054452131.
It is a Harshad number since it is a multiple of its sum of digits (32), and also a Moran number because the ratio is a prime number: 410170157191 = 13125445030112 / (1 + 3 + 1 + 2 + 5 + 4 + 4 + 5 + 0 + 3 + 0 + 1 + 1 + 2).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205085078564 + ... + 205085078627.
It is an arithmetic number, because the mean of its divisors is an integer number (2153393325258).
Almost surely, 213125445030112 is an apocalyptic number.
It is an amenable number.
13125445030112 is a deficient number, since it is larger than the sum of its proper divisors (12715274872984).
13125445030112 is an equidigital number, since it uses as much as digits as its factorization.
13125445030112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 410170157201 (or 410170157193 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13125445030112 its reverse (21103054452131), we get a palindrome (34228499482243).
The spelling of 13125445030112 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-five million, thirty thousand, one hundred twelve".
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