13125452540440 has 16 divisors (see below), whose sum is σ = 29532268216080. Its totient is φ = 5250181016160.

The previous prime is 13125452540423. The next prime is 13125452540483. The reversal of 13125452540440 is 4404525452131.

It is a Harshad number since it is a multiple of its sum of digits (40), and also a Moran number because the ratio is a prime number: 328136313511 = 13125452540440 / (1 + 3 + 1 + 2 + 5 + 4 + 5 + 2 + 5 + 4 + 0 + 4 + 4 + 0).

It is a junction number, because it is equal to n+sod(n) for n = 13125452540393 and 13125452540402.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164068156716 + ... + 164068156795.

It is an arithmetic number, because the mean of its divisors is an integer number (1845766763505).

Almost surely, 2^{13125452540440} is an apocalyptic number.

13125452540440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13125452540440 is an abundant number, since it is smaller than the sum of its proper divisors (16406815675640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13125452540440 is a wasteful number, since it uses less digits than its factorization.

13125452540440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 328136313522 (or 328136313518 counting only the distinct ones).

The product of its (nonzero) digits is 384000, while the sum is 40.

Adding to 13125452540440 its reverse (4404525452131), we get a palindrome (17529977992571).

The spelling of 13125452540440 in words is "thirteen trillion, one hundred twenty-five billion, four hundred fifty-two million, five hundred forty thousand, four hundred forty".