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1312550452021 is a prime number
BaseRepresentation
bin10011000110011010000…
…110100111101100110101
311122110220220020110210111
4103012122012213230311
5133001100403431041
62442551035223021
7163554136521454
oct23063206475465
94573826213714
101312550452021
1146671656a596
1219246a5a7a71
1396a082ca103
1447756332b9b
1524220b77981
hex1319a1a7b35

1312550452021 has 2 divisors, whose sum is σ = 1312550452022. Its totient is φ = 1312550452020.

The previous prime is 1312550452009. The next prime is 1312550452051. The reversal of 1312550452021 is 1202540552131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1189550142225 + 123000309796 = 1090665^2 + 350714^2 .

It is an emirp because it is prime and its reverse (1202540552131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312550452021 - 215 = 1312550419253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312550452051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656275226010 + 656275226011.

It is an arithmetic number, because the mean of its divisors is an integer number (656275226011).

Almost surely, 21312550452021 is an apocalyptic number.

It is an amenable number.

1312550452021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312550452021 is an equidigital number, since it uses as much as digits as its factorization.

1312550452021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 1312550452021 in words is "one trillion, three hundred twelve billion, five hundred fifty million, four hundred fifty-two thousand, twenty-one".