13125543033140 has 12 divisors (see below), whose sum is σ = 27563640369636. Its totient is φ = 5250217213248.

The previous prime is 13125543033103. The next prime is 13125543033151. The reversal of 13125543033140 is 4133034552131.

It can be written as a sum of positive squares in 2 ways, for example, as 6837063989284 + 6288479043856 = 2614778^2 + 2507684^2 .

It is a super-2 number, since 2×13125543033140² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13125543033140.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328138575809 + ... + 328138575848.

It is an arithmetic number, because the mean of its divisors is an integer number (2296970030803).

Almost surely, 2^{13125543033140} is an apocalyptic number.

13125543033140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13125543033140 is an abundant number, since it is smaller than the sum of its proper divisors (14438097336496).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13125543033140 is a wasteful number, since it uses less digits than its factorization.

13125543033140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656277151666 (or 656277151664 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 13125543033140 its reverse (4133034552131), we get a palindrome (17258577585271).

The spelling of 13125543033140 in words is "thirteen trillion, one hundred twenty-five billion, five hundred forty-three million, thirty-three thousand, one hundred forty".