1312583440121 has 2 divisors, whose sum is σ = 1312583440122. Its totient is φ = 1312583440120.

The previous prime is 1312583440099. The next prime is 1312583440123. The reversal of 1312583440121 is 1210443852131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 913102558096 + 399480882025 = 955564^2 + 632045^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312583440121 - 2²⁶ = 1312516331257 is a prime.

It is a Sophie Germain prime.

Together with 1312583440123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1312583440123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656291720060 + 656291720061.

It is an arithmetic number, because the mean of its divisors is an integer number (656291720061).

Almost surely, 2^{1312583440121} is an apocalyptic number.

It is an amenable number.

1312583440121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312583440121 is an equidigital number, since it uses as much as digits as its factorization.

1312583440121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 1312583440121 in words is "one trillion, three hundred twelve billion, five hundred eighty-three million, four hundred forty thousand, one hundred twenty-one".