Base | Representation |
---|---|
bin | 1011111100000011000100… |
… | …0100100101100001110101 |
3 | 1201110212010110121210112121 |
4 | 2333000301010211201311 |
5 | 3210030021243424303 |
6 | 43530040221315541 |
7 | 2523224355325363 |
oct | 277006104454165 |
9 | 51425113553477 |
10 | 13126243342453 |
11 | 420089919146a |
12 | 157bb54405bb1 |
13 | 742a5148c857 |
14 | 335456602633 |
15 | 17b69c7e19bd |
hex | bf031125875 |
13126243342453 has 2 divisors, whose sum is σ = 13126243342454. Its totient is φ = 13126243342452.
The previous prime is 13126243342441. The next prime is 13126243342469. The reversal of 13126243342453 is 35424334262131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7519567605489 + 5606675736964 = 2742183^2 + 2367842^2 .
It is a cyclic number.
It is not a de Polignac number, because 13126243342453 - 237 = 12988804388981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13126243342493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563121671226 + 6563121671227.
It is an arithmetic number, because the mean of its divisors is an integer number (6563121671227).
Almost surely, 213126243342453 is an apocalyptic number.
It is an amenable number.
13126243342453 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126243342453 is an equidigital number, since it uses as much as digits as its factorization.
13126243342453 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1244160, while the sum is 43.
The spelling of 13126243342453 in words is "thirteen trillion, one hundred twenty-six billion, two hundred forty-three million, three hundred forty-two thousand, four hundred fifty-three".
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