Base | Representation |
---|---|
bin | 10011000110011111000… |
… | …110101001011001010111 |
3 | 11122111010202002200101121 |
4 | 103012133012221121113 |
5 | 133001233343020142 |
6 | 2443003233304411 |
7 | 163556205560524 |
oct | 23063706513127 |
9 | 4574122080347 |
10 | 1312634345047 |
11 | 46675995a673 |
12 | 192492705107 |
13 | 96a1c7c145c |
14 | 4776353014b |
15 | 242281e9c67 |
hex | 1319f1a9657 |
1312634345047 has 2 divisors, whose sum is σ = 1312634345048. Its totient is φ = 1312634345046.
The previous prime is 1312634345027. The next prime is 1312634345101. The reversal of 1312634345047 is 7405434362131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312634345047 - 227 = 1312500127319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312634344994 and 1312634345012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312634345027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656317172523 + 656317172524.
It is an arithmetic number, because the mean of its divisors is an integer number (656317172524).
Almost surely, 21312634345047 is an apocalyptic number.
1312634345047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312634345047 is an equidigital number, since it uses as much as digits as its factorization.
1312634345047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 43.
The spelling of 1312634345047 in words is "one trillion, three hundred twelve billion, six hundred thirty-four million, three hundred forty-five thousand, forty-seven".
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