Base | Representation |
---|---|
bin | 111101000111111101… |
… | …1111111010101100101 |
3 | 110112211000011100020002 |
4 | 1322033323333111211 |
5 | 4122312023333233 |
6 | 140145104351045 |
7 | 12324561425132 |
oct | 1721773772545 |
9 | 415730140202 |
10 | 131263886693 |
11 | 5073a050995 |
12 | 21534015485 |
13 | c4bb9a7094 |
14 | 64d32a9589 |
15 | 3633cbd6e8 |
hex | 1e8feff565 |
131263886693 has 2 divisors, whose sum is σ = 131263886694. Its totient is φ = 131263886692.
The previous prime is 131263886639. The next prime is 131263886729. The reversal of 131263886693 is 396688362131.
Together with previous prime (131263886639) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128130350209 + 3133536484 = 357953^2 + 55978^2 .
It is a cyclic number.
It is not a de Polignac number, because 131263886693 - 230 = 130190144869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131263886603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65631943346 + 65631943347.
It is an arithmetic number, because the mean of its divisors is an integer number (65631943347).
Almost surely, 2131263886693 is an apocalyptic number.
It is an amenable number.
131263886693 is a deficient number, since it is larger than the sum of its proper divisors (1).
131263886693 is an equidigital number, since it uses as much as digits as its factorization.
131263886693 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6718464, while the sum is 56.
The spelling of 131263886693 in words is "one hundred thirty-one billion, two hundred sixty-three million, eight hundred eighty-six thousand, six hundred ninety-three".
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